wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

if nacl is doped with 10^ -3 mol% of srcl2 . what is the concentration of cation vacancies?

Open in App
Solution

Given,

NaCl is doped with 10-3 mole % of SrCl2.This means, 100 moles of NaCl are doped with 10-3 moles of SrCl2.

Therefore, 1mole of NaCl is doped with 10-3 /100 = 10-5 moles of SrCl2 or 10-5 moles of Sr2+.

Now,

One Sr2+ ion create one cation vacancy.

Therefore, no. of cation vacancies created by 10-5 moles Sr2+

= 10-5 moles/mole of NaCl

= 10-5 x 6.022 x 1023 / mole of NaCl

= 6.022 x 1018/ mole of NaCl


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Empirical and Molecular Formula
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon