if probability of a ship for getting it safe is 1/5. what is the probability of getting safe 3 ships out of 5?given that getting ships safe is independent from each other.

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Solution

Here the probability of sinking is 1/5
So the probability of non-sinking = 1-1/5 = 4/5

So this is a question of binomial distribution.
Hence n = 5 , p = 4/5 and q = 1/5 and r = 3
So P(3) = ⁵C₃(4/5)³(1/5)²

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if probability of a ship for getting it safe is 1/5. what is the probability of getting safe 3 ships out of 5?given that getting ships safe is independent from each other.

Here the probability of sinking is 1/5 So the probability of non-sinking = 1-1/5 = 4/5 So this is a question of binomial distribution. Hence n = 5 , p = 4/5 and q = 1/5 and r = 3 So P(3) = 5C3(4/5)3(1/5)2

Here the probability of sinking is 1/5
So the probability of non-sinking = 1-1/5 = 4/5

So this is a question of binomial distribution.
Hence n = 5 , p = 4/5 and q = 1/5 and r = 3
So P(3) = ⁵C₃(4/5)³(1/5)²