if the 10th term of an AP is 52 17 th term is 20 more than the 13 th term. find the AP
Let the first term and the common difference of the given A.P. be a and d respectively.
Then,
Second term (a 2) = a + d
Fourth term (a 4) = a + 3d
Eighth term (a 8) = a + 7d
Given : a 8 - a 4 = 16
⇒ a + 7d - (a + 3d) = 16
⇒ a + 7d - a - 3d = 16
⇒ 4d = 16
⇒ d = 16/4 = 4
Also
a 2 = 13
⇒ a + d = 13
⇒ a + 4 = 13
⇒ a = 13 - 4 = 9
Hence, the required A.P. is 9, 13, 17, 21, .....