if the far point of a eye lens is 1 metre . Find the power of lens required to correct the defect .

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Solution

Here,
The focal length will be
F=1.0 m
Therefore, power of lens = 1/1 =1 D

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if the far point of a eye lens is 1 metre . Find the power of lens required to correct the defect .

Here, The focal length will be F=1.0 m Therefore, power of lens = 1/1 =1 D

Here,
The focal length will be
F=1.0 m
Therefore, power of lens = 1/1 =1 D