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Question

If the velocity of a body is doubled, what will be the change in its K.E

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Solution

the kinetic energy is given as

KE = (1/2)mv2

so, if the velocity is doubled the kinetic energy becomes

KE' = (1/2)m(2v)2 = 4[(1/2)mv2]

so,

KE' = 4KE

thus, kinetic energy increases four times.


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