If the velocity of a body is doubled, what will be the change in its K.E
the kinetic energy is given as
KE = (1/2)mv2
so, if the velocity is doubled the kinetic energy becomes
KE' = (1/2)m(2v)2 = 4[(1/2)mv2]
so,
KE' = 4KE
thus, kinetic energy increases four times.