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Question

if the weight of metal oxide is x g containing y g of oxygen, the equivalent mass of metal will be?

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Solution

Weight of metal =(x-y)g

Y g Oxygen = (y/16) moles

Oxide means the O has taken in 2 electrons, i.e. a total of (y/8) mole

Equivalent weight of metal = (x-y)/(y/8)


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