MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Magnetic Field Due to a Straight Current Carrying Conductor

In a coaxial ...

Question

In a coaxial straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero
a) outside the cable
b) inside the inner conductor
c) inside the outer conductor
d) in between the two conductors
Pl. give reason.

Open in App

Solution

a) Outside the cable
This is because the magnetic fields produced by the two wires would be in opposite directions and will cancel each other out.

Suggest Corrections

thumbs-up

0

Similar questions

Q. In a coaxial, straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero :

Q. A coaxial cable consists of a thin inner current carrying wire fixed along the axis of a hollow current carrying tube. Let

B_{1} a n d B_{2}

be the magnetic fields in the region between the conductors and outside the tube respectively, then:

i

ampere flows along the inner conductor of a coaxial cable and returns along the outer conductor of the cable, then the magnetic induction at any point outside the conductor at a distance

r

metre the axis is

Q. The given diagram is a cross-sectional view of coaxial cable. The central conductor is surrounded by a rubber layer, which is surrounded by an outer conductor, which is further surrounded by another rubber layer. Current in the inner conductor is

1 A

directed out of the page, and current in the outer conductor is

3 A

into the page. The ratio of magnitude of magnetic field at point

a

to that at point

b

Q. A solid cylindrical conductor of radius

R_{1}

is kept inside a hollow cylindrical conductor of inner radius

R_{2}

and outer radius

R_{3} (R_{1} < R_{2} < R_{3})

in a co - axial manner, as shown. The solid cylinder carries a current

I_{1}

and the hollow conductor carries current

I_{2}

in the opposite directions. The two conductors are kept insulated from each other and current through each is distributed uniformly over the cross–section. Let r be any radial distance from the axis.

Magnitude of magnetic induction B at points inside the solid conductor, so that

r < R_{1}

, can be expressed as

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Magnetic Field Due to a Current straight Carrying Conductor

PHYSICS

Watch in App

explore_more_icon

Explore more

Magnetic Field Due to a Straight Current Carrying Conductor

Standard X Physics

Join BYJU'S Learning Program

CrossIcon