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Question

In a factory, 5 electric bulbs of power 500W are used for 6 hours and a heater of 2kW is uesd for 8 hours in day. Calculate the energy consumed in 30 days and the cost of the electrical energy @ Rs. 5/unit.

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Solution

Here,

Power of 1 bulb = 500 W

Power of 5 bulbs = 5×500 = 2500W

= 2.5 kW

Time the bulbs glow/ day = 6 hr

Energy consumed in kWh = 6×2.5 = 15 kWh

Power of heater = 2kW

Time the heater is kept on / day = 8 hr

Energy consumed in kWh = 8×2 = 16 kWh

Total consumption / day = 16 + 15 = 31 kWh

Total number of units in 30 days = 30×31 kWh

= 930 kWh

Price of 1 kWh = Rs. 5

Price of 930 kWh = Rs. 5 × 930

= Rs. 4650


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