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Question
in a group of 50 scouts in a camp ,30 are well trained in first aid techniques while the remaining are well trained in hospitality but not in first aid .two scouts are selected at random from the group .find the probaility distribution of the number of selected scouts who are well trained in first aid .find the mean of the distribution also .write one more value which is expected from a well trained scout
in a group of 50 scouts in a camp ,30 are well trained in first aid techniques while the remaining are well trained in hospitality but not in first aid .two scouts are selected at random from the group .find the probaility distribution of the number of selected scouts who are well trained in first aid .find the mean of the distribution also .write one more value which is expected from a well trained scout
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Solution
This can be taken as a binomial distribution.
Probability of selecting one scout who is well trained in first aid = 30/50 = 0.6
Probability of selecting two scouts trained in first aid = 50C2(0.6)2(1 - 0.6)48
Mean of the distribution is equal to 50 x 0.6 = 3.
This can be taken as a binomial distribution.
Probability of selecting one scout who is well trained in first aid = 30/50 = 0.6
Probability of selecting two scouts trained in first aid = 50C2(0.6)2(1 - 0.6)48
Mean of the distribution is equal to 50 x 0.6 = 3.
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