In a hydraulic machine-a force of 2 N is applied on the piston of area of cross section 10 cm2-What force is obtained on its piston of area of cross section 100 cm2

The pressure experienced in both cases would be same. So, asP = F/AF1/A1 = F2/A2or the force on the second piston will beF2 = (F1/A1).A2by substituting appropri ...

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Standard IX

Physics

Pascal's Law

In a hydrauli...

Question

In a hydraulic machine,a force of 2 N is applied on the piston of area of cross section 10 cm².What force is obtained on its piston of area of cross section 100 cm²

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Solution

The pressure experienced in both cases would be same. So, as
P = F/A
F₁/A₁ = F₂/A₂
or the force on the second piston will be
F₂ = (F₁/A₁).A₂
by substituting appropriate values we get
F₂ = (F₁/A₁).A₂
F₂ = (2 / 10x10^-4). 100 x 10^-4
or
the force
F₂ =20 N

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In a hydraulic machine,a force of 2 N is applied on the piston of area of cross section 10 cm2.What force is obtained on its piston of area of cross section 100 cm2

The pressure experienced in both cases would be same. So, asP = F/AF1/A1 = F2/A2or the force on the second piston will beF2 = (F1/A1).A2by substituting appropriate values we getF2 = (F1/A1).A2F2 = (2 / 10x10-4). 100 x 10-4orthe force F2 =20 N

In a hydraulic machine,a force of 2 N is applied on the piston of area of cross section 10 cm².What force is obtained on its piston of area of cross section 100 cm²

The pressure experienced in both cases would be same. So, as
P = F/A
F₁/A₁ = F₂/A₂
or the force on the second piston will be
F₂ = (F₁/A₁).A₂
by substituting appropriate values we get
F₂ = (F₁/A₁).A₂
F₂ = (2 / 10x10^-4). 100 x 10^-4
or
the force
F₂ =20 N