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Question

in an Arithematic progression,if 8thterm is 2times of its 4th term,and 10th term is 30 then,write yhe series

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Solution

T8= 2 T 4 ,

T10=30

Now,
T8= 2 T 4 ,
a + 7d = 2(a+3d)
a = d

Tn= a+(n-1)d

T10=a+(10-1)a

30=10a
a = d =3

Therefore, The series are :

3,6,9....


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