Question

In hydrogen atom the electron makes 6X10(15) revolutions per second around the nucleus. what will be the current in the orbit ?

Answer 1

The electron with charge e=1.6 X 10 ^-19C takes 6 X 10 ¹⁵ revolutions per second.
Current, $I=\frac{q}{t}$
Angular velocity=6 X 10 ¹⁵ rps
$$\begin{gathered} \theta =\omega t \\ Timeintervalfor1revolution,t=\frac{AngularDisplacement}{AngularVelocity}=\frac{\theta }{\omega }=\frac{2\pi rad}{6X{10}^{15}rad/s} \\ I=\frac{1.6X10{}^{-19}X6X{10}^{15}}{2\pi }=1.52X{10}^{-4}A \end{gathered}$$
So, the orbitting electron amounts to a small current of 0.152 mA