In spinel structure- O2-ions are cubic closed packed- whereas 1-8thof the tetrahedral holes are occupied by A2-cations and 1-2 of the octahedral holes are occupied by cations B3- The general formula of this compound is-B2O4

No #160;of #160;oxygen #160;aom #160;= #160;4 #160;(as #160;it #160;is #160;a #160;ccp)No #160;of #160;octahedral #160;voids #160;= ...

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Standard X

Chemistry

Formation of NaCl Lattice

In spinel str...

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In spinel structure, O²^-ions are cubic closed packed, whereas 1/8^thof the tetrahedral holes are occupied by A²⁺cations and 1/2 of the octahedral holes are occupied by cations B³⁺. The general formula of this compound is

B2O4

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Solution

$N o o f o x y g e n a o m = 4 (a s i t i s a c c p) N o o f o c t a h e d r a l v o i d s = 4 n o o f t e t r a h e d r a l v o i d s = 8 N o o f A^{2 +} c a t i o n = 8 \times \frac{1}{8} = 1 N o o f B^{3 +} c a t i o n = 4 \times \frac{1}{2} = 2 T h u s t h e f o r m u l a i s = A B_{2} O_{4}$

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In spinel structure, O2-ions are cubic closed packed, whereas 1/8thof the tetrahedral holes are occupied by A2+cations and 1/2 of the octahedral holes are occupied by cations B3+. The general formula of this compound is B2O4

No of oxygen aom = 4 (as it is a ccp)No of octahedral voids = 4no of tetrahedral voids = 8No of A2+ cation = 8 × 18 =1No of B3+ cation = 4 × 12 =2 Thus the formula is = AB2O4

In spinel structure, O²^-ions are cubic closed packed, whereas 1/8^thof the tetrahedral holes are occupied by A²⁺cations and 1/2 of the octahedral holes are occupied by cations B³⁺. The general formula of this compound is

B2O4

$N o o f o x y g e n a o m = 4 (a s i t i s a c c p) N o o f o c t a h e d r a l v o i d s = 4 n o o f t e t r a h e d r a l v o i d s = 8 N o o f A^{2 +} c a t i o n = 8 \times \frac{1}{8} = 1 N o o f B^{3 +} c a t i o n = 4 \times \frac{1}{2} = 2 T h u s t h e f o r m u l a i s = A B_{2} O_{4}$