In the reaction 2A2 + 3B2 ---> 2A2B3
Identify the limiting reagent
2 A2 + 3 B2 → 2 A2B3.
2 moles of A2 will react with 3 moles of B2.
1 mole of A2 will react with 1.5 moles of B2.
2 mole of B2 will react with (2x2)/3 = 1.33 mole of A2.
Thus in second case A2. will be the limiting reagent.
4 mole atoms of A will react with 6 mole atoms of B.
100 mole atoms of A will react with (6x100)/4 = 150 mole atoms of B.
In third case B is the limiting reagent.