in Young"s double slit experiment the slits are 0.5mm apart & interferance is observed at adistance of 100cm from the slits.It is found that the 9 th bright fringe is at a distance 8.835mm from a second dark fringe from the center of the fringe patern,then what is the wavelength of light used?

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Solution

d = 0.5×10^-3m
D = 1 m
Distance of a 9^th bright fringe is given by
y_n = 9λD/d
Distance of a 2^nd dark fringe is given by
y_s = (2×1+1)λD/2d = 3 λD/2d
Given
y_n – y_s = 8.835×10^-3m
=> (9 -3 /2) λD/d = 8.835×10^-3
=>7.5×λ×1/0.5×10^-3= 8.835×10^-3
=> λ=0.589×10^-6 m
=> λ=5890×10^-10 m = 5890 Angstrom

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in Young"s double slit experiment the slits are 0.5mm apart & interferance is observed at adistance of 100cm from the slits.It is found that the 9 th bright fringe is at a distance 8.835mm from a second dark fringe from the center of the fringe patern,then what is the wavelength of light used?

d = 0.5×10-3mD = 1 mDistance of a 9th bright fringe is given byyn = 9λD/dDistance of a 2nd dark fringe is given byys = (2×1+1)λD/2d = 3 λD/2dGivenyn – ys = 8.835×10-3m=> (9 -3 /2) λD/d = 8.835×10-3=>7.5×λ×1/0.5×10-3 = 8.835×10-3=> λ=0.589×10-6 m=> λ=5890×10-10 m = 5890 Angstrom