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Question

'P' is a point inside the triangle ABC, such that BC(PA)+CA(PB)+AB(PC)=0, then for the triangle ABC the point P is its :

A
Incentre
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B
Circumcentre
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C
Centroid
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D
Orthocentre
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Solution

The correct option is B Incentre
Given that, P is a point inside the triangle ABC, such that BC(PA)+CA(PB)+AB(PC)=0
Let, BC=a,CA=b,AB=c and OA=¯a,OB=¯b,OC=¯c

a(¯aOP)+b(¯bOP)+c(¯cOP)=0
OP=a¯a+b¯b+c¯ca+b+c
P is an Incentre of triangle ABC.
Hence, option A.

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