'P' is a point inside the triangle ABC, such that BC(→PA)+CA(→PB)+AB(→PC)=0, then for the triangle ABC the point P is its :
A
Incentre
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B
Circumcentre
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C
Centroid
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D
Orthocentre
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Solution
The correct option is B Incentre Given that, P is a point inside the triangle ABC, such that BC(→PA)+CA(→PB)+AB(→PC)=0 Let, BC=a,CA=b,AB=c and →OA=¯a,→OB=¯b,→OC=¯c