P is a point on the hyperbola x23−y25=1, N is the foot of the perpendicular from P on the transverse axis . The tangent to the hyperbola at P meets the transverse axis at T . If O is the centre of the hyperbola, then find the value of OT . ON .
A
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is D3 OT=acosθ ; ON=asecθ⇒OT.ON=a2