$P$ is a point on the line joining $A (4, 3)$ and $B (- 2, 6)$ such that $5 A P = 2 B P$ . Find the coordinates of $P$ .

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Solution

Given $\frac{A P}{B P} = \frac{2}{5}$
Using section formula, we get
$P (x, y) = (\frac{(5) (4) + (2) (- 2)}{7}, \frac{(5) (3) + (2) (6)}{7})$
$P (x, y) = (\frac{16}{7}, \frac{27}{7})$

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P is a point on the line joining A(4,3) and B(−2,6) such that 5AP=2BP. Find the coordinates of P.

Given APBP=25Using section formula, we get P(x,y)=((5)(4)+(2)(−2)7,(5)(3)+(2)(6)7)P(x,y)=(167,277)

$P$ is a point on the line joining $A (4, 3)$ and $B (- 2, 6)$ such that $5 A P = 2 B P$ . Find the coordinates of $P$ .

Given $\frac{A P}{B P} = \frac{2}{5}$
Using section formula, we get
$P (x, y) = (\frac{(5) (4) + (2) (- 2)}{7}, \frac{(5) (3) + (2) (6)}{7})$
$P (x, y) = (\frac{16}{7}, \frac{27}{7})$