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Question

P is a point outside a circle. From point P two rays are drawn to a circle which meet circle only at one point each. Let these 2 points be Q and R. The centre of circle is O. Which of the following statements is true and because of which property?


A

PQ = PO, triangle congruency

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B

PR = PO, angle bisection

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C

PQ = PR, triangle congruency

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D
RQ = (OQ+OR), straight line
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Solution

The correct option is C

PQ = PR, triangle congruency


Refer to above figure.

Line segments PQ and PR touch circle at only one point. Thus PQ and PR are tangents to circle.

Consider OQP and ORP,

Since Q and R lie on circumference, OR = OQ = radius.

[By Theorem- Tangents are perpendicular to radii at point of contact]
Thus tangents PQ and PR are perpendicular to corresponding radii OQ and OR respectively.

So, PQO = ROP = 90

Since OP is a common side between the 2 triangles, OP = OP = common side.

Thus by RHS congruency, triangles PQO and PRO are congruent.

Hence it is clear that PQ = PR since these 2 sides are corresponding sides in the 2 congruent triangles.

PQ and PR are nothing but the tangents from P to circle. This property will hold true for any pair of tangents drawn from an external point to a circle.


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