P is a point outside the circle as shown. MP and NP are the tangents are drawn to the circle from this point. Then △OMP ≅ △ONP.
True
In △OMP and △ONP,
OM = ON [radius]
OP = OP [common side]
∠OMP = ∠ONP [right angle triangle]
So, by R.H.S criterion,
△OMP ≅ △ONP
That is the triangles on either side of OP are congruent.