P is a variable point on the ellipse x2a2+y2b2=1 with AA’ as the major axis. Then the maximum value of the area of △APA′ is
A
ab
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B
2ab
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C
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D
none
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Solution
The correct option is A ab The triangle APA’ has maximum area when P coincides with B (end point of minor axis). ∴ Maximum area of △APA′ is OB = 12 2a.b = ab