wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

P is a variable point on the line L=0. Tangents are drawn to the circle x2+y2=4 from P to touch it at Q and R. The parallelogram PQRS is completed.
If P(6,8), then the area of QRS is

A
196525 sq. unit
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
196652 sq. unit
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
192625 sq. unit
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
196525 sq. unit
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 192625 sq. unit

As PQRS is a parallelogram
area of QRS= area of PQR
So area of QRS=L3rL2+r2
=S3/21rS1+r2=(96)3/2296+4=192625 sq. units

Alternate Solution:
P(6,8)
Equation of QR is 6x+8y=4
3x+4y2=0
PM=485 and PQ=96
QM=96(48)225=9625
QR=29625
area of PQR=12PMQR=192625
PQRS is a rhombus
area of QRS=area of PQR=192625 sq. units

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Tangent to a Circle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon