$P$ is any point inside the triangle $A B C$ . Hence $∠ B P C > ∠ B A C$ .

True

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False

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Ambiguous

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Data insufficient

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Solution

The correct option is A True
Let
$∠ P B C = x$ and $∠ P C B = y$
$=> ∠ B P C = 180 - (x + y)$
Let
$∠ A B P = z$ and $∠ A C P = w$
$=> ∠ B A C = 180 - (x + z) - (y + w)$
$=> ∠ B A C = 180 - (x + y) - (w + z)$
$∠ B A C = ∠ B P C - (w + z)$
$=> ∠ B P C = ∠ B A C + (w + z)$
$=> ∠ B P C > ∠ B A C$

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Similar questions

P

A B C

∠ B P C > ∠ B A C

P

A B C

∠ B P C > ∠ B A C

P is any point inside the triangle ABC therefore $∠ B P C < ∠ B A C$ .

If the above statement is true then mention answer as 1, else mention 0 if false

△ A B C

∠ P B A = 20^{\circ}, ∠ B A C = 50^{\circ} a n d ∠ P C A = 35^{\circ}

∠ B P C

P

Δ A B C

∠ P B A = 20^{\circ}, ∠ B A C = 50^{\circ} a n d ∠ P C A = 35^{\circ}

∠ B P C

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