Question

$P$ is any point on base $BC$ of $△ABC$ and $D$ is the mid-point of $BC$. $DE$ is drawn parallel to $PA$ to meet $AC$ at $E$. If $ar\left(△ABC\right)=12c{m}^2$ , then find area of $△EPC$.

Answer 1

Given

area $\left(△ABC\right)=12c{m}^2$

$ABC$ is a triangle and $D$ is the midpoint of $BC$ and $P$ is a point on $BC$ such that $DE||PA$

So, area $\left(△EPC\right)=\frac{1}{2}$ area $\left(△ABC\right)$

$=\frac{1}{2}\times 12=6c{m}^2$

Hence area $\left(△EPC\right)=6c{m}^2$