Question

P is in exterior of $C(0,15)$. A tangent from P touches the circle at T.If $PT=8$,then OP$=$

• A. $17$
• B. $13$
• C. $23$
• D. $7$

Answer 1

The correct option is A $17$

We know, tangent of circle at point of contact making right angle with the radius.

Hence, using Pythagoras Theorem in $△OTP,$

${OT}^2+{PT}^2={OP}^2$

${15}^2+8^2={OP}^2$

${OP}^2=125+64=189$

$OP=17$ units