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Question

P is point in the plane of the triangle ABC. pv's of A,B and c. a,b and c respectively with respect to P as the origin.
If (b+c)(bc)=0 and (c+a)(ca)=0 then w.r.t. the triangle ABC,P is its

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Solution

(b+c)(bc)=0b2|c|2=0|a|=b=|c|(c+a)(ca)=0|c|2|a|2=0|c|=|a|

Implies P is cir-cum center of triangle

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