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Question

P is the centre of the circle . Prove that XPZ=2(XZY+YXZ). [3 MARKS]

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Solution

Concept: 1 Mark
Steps: 1 Mark
Answer: 1 Mark

Given: A circle with centre P and XY, YZ are the two chords.

To prove:
XPZ=2(XZY+YXZ)

Proof: In a circle with centre P, arc XY subtends XPY at the centre and XZY at remaining part of the circle.

XPY=2XZY .......(1)

Similarly, arc YZ subtends YPZ at the centre and YXZ at remaining part

YPZ=2YXZ ........(2)

Adding (1), and (2), we get

XPY+YPZ=2XZY+2YXZ

XPZ=2(XZY+YXZ)


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