P is the centre of the circle . Prove that ∠XPZ=2(∠XZY+∠YXZ). [3 MARKS]
Concept: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Given: A circle with centre P and XY, YZ are the two chords.
To prove:
∠XPZ=2(∠XZY+∠YXZ)
Proof: In a circle with centre P, arc XY subtends ∠XPY at the centre and ∠XZY at remaining part of the circle.
∠XPY=2∠XZY .......(1)
Similarly, arc YZ subtends ∠YPZ at the centre and ∠YXZ at remaining part
∠YPZ=2∠YXZ ........(2)
Adding (1), and (2), we get
∠XPY+∠YPZ=2∠XZY+2∠YXZ
∠XPZ=2(∠XZY+∠YXZ)