You visited us 1 times! Enjoying our articles? Unlock Full Access!

Basic Buffer Action

pKb for NH4...

Question

$p K_{b}$ for ${N H}_{4} O H$ at certain temperature is $4.74$ . The pH of basic buffer containing equimolar concentration of ${N H}_{4} O H$ and ${N H}_{4} C l$ will be?

7.74

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.74

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.37

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9.26

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $9.26$
$p O H = p K b + l o g$ (conjugate acid)/(base)
Concentration of $N H_{4} C l$ = Concentration of $N H_{4} O H$
$p O H = p K b + l o g 1 = p K b$
$p H = 14 - p O H$
$= 14 - p k b$
$= 14 - 4.74$
$= 9.26$

Suggest Corrections

Similar questions

p K_{b}

N H_{4} O H

N H_{4} O H

N H_{C} I

N H_{3} a n d N H_{4}^{+} C l^{-}

m o l L^{- 1} .

p K_{b}

N H_{3} = 4.7, l o g 2 = 0.3

{N H}_{4} C l

{N H}_{4} O H

{O H}^{-}

p K_{a}

N H_{4}^{+}

9.26

N H_{4} O H - N H_{4} C l

p H

H_{2} O

{N H}_{4} C l / {N H}_{4} O H

{N H}_{4} O H / {N H}_{4} C l

Join BYJU'S Learning Program