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pH the Power of H

pK b of NH4OH...

Question

p $K_{b}$ of $N H_{4} O H$ is 5. The pH of a mixture containing 10 mL of 0.3 M $N H_{4} O H$ and 200 mL of 0.1 M $({NH}_{4})_{3} {PO}_{4}$
rounded to the nearest integer is?
8

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Solution

The correct option is A 8
Millimoles of $N H_{4} O H$ = 10 x 0.3= 3

Millimoles of $({NH}_{4})_{3} {PO}_{4}$ =200 x 0.1 x 3=60

pOH = 5 + log $\frac{60}{3}$ = 5 + log20 = 6.3010

pH = 14- 6.3010 = 7.6987

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