K I + Cl2 ---- KCl + I2 how to devide it in two half reactions?

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Solution

K I + Cl2 ---- KCl + I2
In the given reaction,
I^- ---------> I (reduction)
Cl ---------> Cl^- (oxidation)
it should be noted that atoms, in their elemental form possess oxidation state as 0.

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