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Question

kishan sells x kg of apples at the rate of rs 80 per kg.some oranges at rs.40 per kg along that he sells 10 kg pomegranate at the rate of rs.120 per kg.find:

a)write an eq. for total cost of quantity

b)write an eq.of total quantity.

c)find the degree.

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Solution

Answer :

Given

Kishan sells

x kg of apples ate the rate of 80 / kg

And
Let he sells y kg oranges at the rate of 40 / kg

And

10 kg pomegranate at the rate of 120 / kg

So,

a ) Equation of total cost is

Total Cost = 80x + 40y + 1200 ( Ans )


b ) Equation of total quantity is

Total quantity = x + y​ + 10 ( Ans )

c ) we know degree of equation is the highest degree of variable , here highest degree is one so ,

Degree = one ( Ans )

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