Long answer type questions
Q11 Two stones are thrown vertically upwards simultaneously with their initial velocities u₁and u₂respectively. Prove that height reached by them would be in the ratio of

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Solution

We know at the top most point velocity will be zero.
$t h e r e f o r e v_{1} = u_{1} + a t_{1} t_{1} i s t h e t i m e i n w h i c h s t o n e s r e a c h e s t o h e i g h t h_{1} A c c e l e r a t i o n i n u p w a r d m o t i o n i s a l w a y s - g . n o w w e g e t 0 = u_{1} - g t_{1} t_{1} = \frac{u_{1}}{g} D i s \tan c e t r a v e l l e d i n t i m e t_{1} : h_{1} = u_{1} t_{1} + \frac{1}{2} a {t_{1}}^{2} h_{1} = u_{1} (\frac{u_{1}}{g}) - \frac{1}{2} g {(\frac{u_{1}}{g})}^{2} h_{1} = \frac{{u_{1}}^{2}}{2 g} S i m i l a r l y w e c a n s o l v e f o r s e c o n d s t o n e a n d w e g e t, h_{2} = \frac{{u_{2}}^{2}}{2 g} \frac{h_{1}}{h_{2}} = \frac{{u_{1}}^{2}}{{u_{2}}^{2}}$

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Long answer type questionsQ11 Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that height reached by them would be in the ratio of

Long answer type questions
Q11 Two stones are thrown vertically upwards simultaneously with their initial velocities u₁and u₂respectively. Prove that height reached by them would be in the ratio of