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Question

Mercuryhas an angle of contact equal to 140° with soda lime glass. Anarrow tube of radius 1.00 mm made of this glass is dipped in atrough containing mercury. By what amount does the mercury dip downin the tube relative to the liquid surface outside? Surface tensionof mercury at the temperature of the experiment is 0.465 N m–1.Density of mercury = 13.6 × 103kg m–3.

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Solution

Angle of contactbetween mercury and soda lime glass, θ= 140°

Radius of the narrowtube, r = 1 mm = 1 ×10–3 m

Surface tension ofmercury at the given temperature, s = 0.465 N m–1

Density of mercury, ρ=13.6 × 103 kg/m3

Dip in the height ofmercury = h

Acceleration due togravity, g = 9.8 m/s2

Surface tension isrelated with the angle of contact and the dip in the height as:

Here, the negative signshows the decreasing level of mercury. Hence, the mercury level dipsby 5.34 mm.


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