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Question

Mr. X has invested a part of his investment in 10% bond A and a part in 15% bond B. His interest income during first year is Rs. 4000. If he invests 20% more in 10% bond A and 10% more in 15% bond B, his income during the second year increases by Rs. 500. Find his initial investment using matrix method

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Solution

Here, let x and y be the investments in 10% bonds and 15% bonds respectively.
So, according to the given question,
0.10x+0.15y=40002x+3y=80000 ... (1)

Now, it is given that if he invests 20% more in 10% bond A and 10% more in 15% bond B, his income during the second year increases by Rs 500.
So,
0.10x+x5+0.15y+y10=45000.106x5+0.1511y10=4500

Solving further,
24x+33y=90000038x+11y=9000008x+11y=300000 ... (2)

Now, solve equation (1) and (2) using matrices.
23811xy=80000300000

So,
X=A-1BX=1AadjAB

Now,
A=211-83A=22-24A=-2

Also,
adjA=11-3-82

Thus,
X=-1211-3-8280000300000X=-12-112324-180000300000X=-440000+450000320000-300000X=1000020000

Therefore, the new investment in 10% bond A is Rs 10000 and 15% bond B will be Rs 20000

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