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Question

npr=npr+1 and ncr=ncr+1 find the values of n and r?

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Solution

Pr =nPr+1 and nCr =nCr+1nPr =nPr+1n!(n-r)!=n!(n-r-1)!n!(n-r)(n-r-1)!=n!(n-r-1)!(n-r)=1 (i)and

n
Cr =nCr+1

n!/ (r! (n - r)!) = n!/ ((r + 1)! (n - r - 1)!)

n!/ (r! (n - r) (n - r - 1)!) = n!/((r + 1) r! (n - r - 1)!)

(n - r) = (r + 1) --------(ii),


from (i) and (ii) we get r = 0, n = n!

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