Question

(numerical question):-HOW FAR APART TWO PROTONS BE IF THE ELECTROSTATICS FORCE EXERTED BY ONE ON THE OTHER IS EQUAL TO WEIGHT OF THE ELECTRON ?

Answer 1

Force between two charges is given by
F=kq₁q₂/r²
Here F=mass of electron
=9.1*10^-31kg
F=9.1*10^-31N
Charge on proton is 1.6 *10^-19c
Putting in equation

9.1*10^-31=9*10⁹ (1.6 *10^-19)²/r²
r ²= 9*10⁹ (1.6 *10^-19)²/9.1*10^-31
2.53*10² m
r= 15.90 m