$P_{(A)}^{o}$ = 60 mm of Hg and $P_{(B)}^{o}$ = 45mm of Hg. If 1 mol of A and 2 mol of B are mixed, the solution forms an azeotropic mixture with a minimum boiling point, then mole fraction of A in its vapour phase above the solution will be

\frac{2}{5}

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\frac{3}{5}

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\frac{2}{3}

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\frac{1}{3}

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Solution

The correct option is D $\frac{1}{3}$
An azeotrope has the same mole fraction in the vapour phase as the solution phase

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Po(A) = 60 mm of Hg and Po(B) = 45mm of Hg. If 1 mol of A and 2 mol of B are mixed, the solution forms an azeotropic mixture with a minimum boiling point, then mole fraction of A in its vapour phase above the solution will be

The correct option is D 13An azeotrope has the same mole fraction in the vapour phase as the solution phase

$P_{(A)}^{o}$ = 60 mm of Hg and $P_{(B)}^{o}$ = 45mm of Hg. If 1 mol of A and 2 mol of B are mixed, the solution forms an azeotropic mixture with a minimum boiling point, then mole fraction of A in its vapour phase above the solution will be

The correct option is D $\frac{1}{3}$
An azeotrope has the same mole fraction in the vapour phase as the solution phase