Question

$P_{\left(A\right)}^o$ = 60 mm of Hg and $P_{\left(B\right)}^o$ = 45mm of Hg. If 1 mol of A and 2 mol of B are mixed, the solution forms an azeotropic mixture with a minimum boiling point, then mole fraction of A in its vapour phase above the solution will be

• A. $\frac{2}{5}$
• B. $\frac{3}{5}$
• C. $\frac{2}{3}$
• D. $\frac{1}{3}$

Answer 1

The correct option is D $\frac{1}{3}$

An azeotrope has the same mole fraction in the vapour phase as the solution phase