on a 60km straight road a bus trvels the first 30km with a uniform speed of 30km/h. how fast must the bus travel the next 30km so as to have average speed of 40km/h. for the entire trip?

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Solution

t₁= time taken when going with speed of 30km/hr = 1hr, and t₂ = time taken to cover next 30 km
$a v e r a g e s p e e d = \frac{t o t a l d i s \tan c e}{t o t a l t i m e} 40 = \frac{60}{1 + t_{2}} 1 + t_{2} = 1.5 t_{2 =} 1.5 - 1 = 0.5 hrs d i s t a n c e c o v e r e d i n t_{2} i s 30 k m n o w u \sin g f o r m u l a s p e e d = \frac{d i s \tan c e}{t i m e (t_{2})} = \frac{30}{0.5} = 60 km / hr$

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