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Question

on a morning walk 3 persons step off together and their steps measure 40 cm , 42 cm and 45 cm respectively what is the minimum distance each should walk so that each can cover the same distance in complete steps

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Solution

The minimum distance that they all three should walk will be the L.C.M. of 40, 42, 45.

Since 40=2×2×2×5

42=2×3×7

45=3×3×5

∴ L.C.M. of 40, 42 and 45 = 2×2×2×3×3×5×7= 2520cm = 25.20m


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