One mole of Chlorine combines with certain weight of a metal giving 111g of its chloride. the same amount of metal can displace 2g of hydrogen from an acid. what is the atomic weight of the metal?
One mole of Chlorine combines with certain weight of a metal giving 111g of its chloride. the same amount of metal can displace 2g of hydrogen from an acid. what is the atomic weight of the metal?
let metal be x
Let us assume the metal to be x
Cl2 + x → n* xCl ( n moles)
1 mole of Cl2 contains 71 grams, 71 g of Cl2 gives us 111 g of the metal chloride
We know that it replaces 2g H , i.e. in other words replacing 2 moles of H or 2+ charge
Therefore, our metal has 2+ charge as Ca, Mg etc or 2 moles of metal like Na, K etc.....
as Cl ha 1- charge so its two moles are used in the metal chloride as:
XCl2 type ( for Ca type metals )
2XCl type (for Na type)
so weight of chloride = 111= 2* 35.5 + x
x=40
We know that, Ca and K has this much mass but K has 1 charge so it should use its two moles thus giving us a final weight of 80g
Since, x is 40 g.
Our metal is Calcium with an atomic weight of 40.
let metal be x
Let us assume the metal to be x
Cl2 + x → n* xCl ( n moles)
1 mole of Cl2 contains 71 grams, 71 g of Cl2 gives us 111 g of the metal chloride
We know that it replaces 2g H , i.e. in other words replacing 2 moles of H or 2+ charge
Therefore, our metal has 2+ charge as Ca, Mg etc or 2 moles of metal like Na, K etc.....
as Cl ha 1- charge so its two moles are used in the metal chloride as:
XCl2 type ( for Ca type metals )
2XCl type (for Na type)
so weight of chloride = 111= 2* 35.5 + x
x=40
We know that, Ca and K has this much mass but K has 1 charge so it should use its two moles thus giving us a final weight of 80g
Since, x is 40 g.
Our metal is Calcium with an atomic weight of 40.
