An object of 2 cm height is placed at a distance of 12 cm from a concave mirror of focal length 15 cm. Find the position, nature and size of the image.
According to question,
h = 2cm, h' = ?
u =-12cm , v = ?
f = -15cm
according to mirror formula
1/v + 1/u = 1/f
1/v + 1/-12 = -1/15
1/v = -1/15+ 1/12
v = 60cm
Thus, image formed is virtual.
For height of image
m = h'/h =- v/u
h' = -(v×h)/u
= (60×2)/12 = 10cm
Hence image formed is virtual and erect and enlarged