14. If a stone is thrown vertically upwards to a height of 9.8m, calculate
(i) (ii)

(i) (ii)

the velocity with which it was thrown and
time taken by it to reach the highest point. Take g = 10m/s2

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Solution

Let the initial velocity be ‘u’ and the time taken to reach the maximum height be ‘t’.
Acceleration due to gravity is = -10 m/s²
Using,
v² = u² + 2as
=> 0 = u² + 2(-10)(9.8)
=> u = 14 m/s
Again,
v = u + at
=> 0 = 14 – 10t
=> t = 1.4 s

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14. If a stone is thrown vertically upwards to a height of 9.8m, calculate(i) (ii) (i) (ii) the velocity with which it was thrown and time taken by it to reach the highest point. Take g = 10m/s2

Let the initial velocity be ‘u’ and the time taken to reach the maximum height be ‘t’.Acceleration due to gravity is = -10 m/s2Using,v2 = u2 + 2as=> 0 = u2 + 2(-10)(9.8)=> u = 14 m/sAgain,v = u + at=> 0 = 14 – 10t=> t = 1.4 s

14. If a stone is thrown vertically upwards to a height of 9.8m, calculate
(i) (ii)

(i) (ii)

the velocity with which it was thrown and
time taken by it to reach the highest point. Take g = 10m/s2

Let the initial velocity be ‘u’ and the time taken to reach the maximum height be ‘t’.
Acceleration due to gravity is = -10 m/s²
Using,
v² = u² + 2as
=> 0 = u² + 2(-10)(9.8)
=> u = 14 m/s
Again,
v = u + at
=> 0 = 14 – 10t
=> t = 1.4 s