P + HNO3 → H3PO4 + NO2 + H2O solve by ion electron method
P + HNO3 → H3PO4 + NO2 + H2O
Oxidation half reaction - P → H3PO4
Reduction half reaction - HNO3 → NO2
Balance oxidation half reaction:
P + 4 H2O → H3PO4 + 5H+
Balance the charge in the above reaction:
P + 4 H2O → H3PO4 + 5H++ 5e- ---------------(1)
Balance reduction half reaction:
HNO3 + H+ → NO2 + H2O
Balance the charge:
HNO3 + H+ + e- → NO2 + H2O
Multiply reduction half reaction with 5 to make the number of electrons in oxidation and reduction reaction equal.
5 HNO3 + 5H+ + 5e- → 5 NO2 + 5 H2O -----(2)
Add (1) and (2) and cancel same substances.
P + 5 HNO3 → H3PO4 + 5 NO2 + H2O
This is the balanced equation.