If the momentum of an electron is changed by P,then the de Brogile wavelength associated with it changes by 0.5%.what is the intial momentum of electron?

Open in App

Solution

As, we know that :
$λ = \frac{h}{p} . . . . . . . (1) L e t p_{0} b e t h e i n i t i a l m o m e n t u m a n d p b e t h e d e c r e a s e i n m o m e n t u m w h e n w a v e l e n g t h c h a n g e s b y 0.5 % . [λ + \frac{0.5}{100} λ] = \frac{h}{p_{0} - p} \frac{100.5 λ}{100} = \frac{h}{p_{0} - p} . . . . . . . (2) f r o m e q . 1 a n d e q . 2 : \frac{100.5 λ}{100} = \frac{λ p}{p_{0} - p} \frac{100.5}{100} = \frac{p}{p_{0} - p} O n s o l v i n g, w e g e t : p_{0} = 1.99 p$

Suggest Corrections

Similar questions

Q. If the momentum of an electron is changed by

Δ p,

then the de-Brogile wavelength associated with it changes by

0.05 %

. The initial momentum of electron will be :

Q. If the momentum of an electron is changed by

P

, then the de-Broglie wavelength associated with it changes by

0.5

. The initial momentum of electron will be :

Q. If the momentum of an electron is increased by

P_{m}

then the de Broglie wavelength associated with it changes by

0.5

%. Then the initial momentum of the electron is

Q. Find the initial momentum of electron if the momentum of electron is changed by

P m

and the de Broglie wavelegth associated with it changes by

0.50

If the momentum of an electron is increased by $Δ p$ , then the de-Broglie wavelength associated with it changes by 0.50%. The initial momentum of the electron will be

Join BYJU'S Learning Program

If the momentum of an electron is changed by P,then the de Brogile wavelength associated with it changes by 0.5%.what is the intial momentum of electron?

As, we know that : λ = hp .......(1)Let p0 be the initial momentum and p be the decrease in momentum when wavelength changes by 0.5 %.λ + 0.5100 λ = hp0 - p100.5 λ100 = hp0 - p .......(2)from eq. 1 and eq. 2 :100.5 λ100 = λpp0 - p100.5 100 = pp0 - pOn solving, we get :p0 = 1.99 p