Question

Q2. A spherical Gaussian surface enclosed a charge of 8.85x10‐8C.

(i) Calculate the electric flux passing through the surface.

(ii) If the radius of the Gaussian surface is doubled, how would the flux change?

Answer 1

(i)

we know that the flux linked with a Gaussian surface is given as

Φ = E.ds = q/ε₀

here,

q = 8.85x10^-8 C

ε₀ = 8.85x10^-12 F/m

so,

Φ = 8.85x10^-8 / 8.85x10^-12

thus, flux will be

Φ = 10⁴ Nm²/C

.

(ii)

The flux does not depend upon the size of the Gaussian surface but only on the charges enclosed. So, in this case also

Φ = 10⁴ Nm²/C.