PbO2 - Cl- - Pb-OH-3 - ClO-how to balance this reaction by half reaction method-

Divide the given reaction into two half reactions:Reduction half reaction: PbO2 â†’ Pb(OH)3 Oxidation half reaction: nbsp; Cl nbsp;â†’ ClO Since other ato ...

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Byju's Answer

Standard XII

Chemistry

Preparation of Alkyl Halides

PbO2 + Cl- =...

Question

PbO₂+ Cl^- = Pb(OH)₃+ ClO^-
^{how to balance this reaction by half reaction method?}

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Solution

Divide the given reaction into two half reactions:
Reduction half reaction: PbO₂ â†’ Pb(OH)₃^-
Oxidation half reaction: Cl^- â†’ ClO^-
Since other atoms are balanced, balance O and H atoms by adding H⁺ and H₂O in both equations:
PbO₂ + H⁺ + H₂O â†’ Pb(OH)₃^-
Cl^- + H₂O â†’ ClO^- + 2H⁺
Balance charge by adding electrons in both the reactions:
PbO₂ + H⁺ + H₂O + 2e â†’ Pb(OH)₃^-
Cl^- + H₂O â†’ ClO^- + 2H⁺ + 2e
Since the number of electrons lost and gained are same, add both the reactions:
PbO₂+ 2 H₂O +Cl^- â†’ Pb(OH)₃^-+ ClO^- + H⁺
The reaction occurs in basic medium, so add OH^- on both sides of the equation:
PbO₂ + 2 H₂O +Cl^- + OH^- â†’ Pb(OH)₃^-+ ClO^- + H⁺ + OH^-
PbO₂ + 2 H₂O +Cl^- + OH^- â†’ Pb(OH)₃^-+ ClO^- + H₂O ( since H^-+ + OH^- = H₂O)
The balanced equation is:
PbO₂ + H₂O +Cl^- + OH^- â†’ Pb(OH)₃^-+ ClO^-

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PbO2 + Cl- = Pb(OH)3 + ClO-how to balance this reaction by half reaction method?

PbO₂+ Cl^- = Pb(OH)₃+ ClO^-
^{how to balance this reaction by half reaction method?}