$p$ pens are packed in each of $10$ boxes $9$ pens are left over. Find a rule of determine the total number of pens.

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Solution

We have,

Box of pens $= 10$

Left over pens $= 9$

Then, number of choosing pens

$=^{10} P_{9}$

$= \frac{10!}{(10 - 9)!}$

$= \frac{10!}{1!}$

$= 10!$

Hence, this is the answer.

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p pens are packed in each of 10 boxes 9 pens are left over. Find a rule of determine the total number of pens.

We have, Box of pens=10 Left over pens=9 Then, number of choosing pens =10P9 =10!(10−9)! =10!1! =10! Hence, this is the answer.

$p$ pens are packed in each of $10$ boxes $9$ pens are left over. Find a rule of determine the total number of pens.

We have,

Box of pens $= 10$

Left over pens $= 9$

Then, number of choosing pens

$=^{10} P_{9}$

$= \frac{10!}{(10 - 9)!}$

$= \frac{10!}{1!}$

$= 10!$

Hence, this is the answer.