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Standard VIII

Mathematics

Place Value and Expanded Form of a Number

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Question

plesae answer this question fast before 26th June 2014
a) A B x 3 =1 B B
Find B and Aif each letter stands for a digit
b) A B x 3 = CAB
Find C, B, and A if each letter stands for a digit
c) 2 A B + A B 1 = 828
Find A and B if each letter stands for a digit
d) 1 2 A + 6 A B = A 0 9
Find A and B if each letter stands for a digit

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Solution

$b) AB \times 3 = CAB \Rightarrow 50 \times 3 = 150 so; A = 5; B = 0 and C = 1 c) 2 AB + AB 1 = 828 \Rightarrow 257 + 571 = 828 So; A = 5; B = 7$

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b) AB×3 = CAB⇒50×3 = 150so; A = 5; B = 0 and C = 1c) 2AB+AB1 = 828⇒257+571 = 828So; A = 5; B = 7

$b) AB \times 3 = CAB \Rightarrow 50 \times 3 = 150 so; A = 5; B = 0 and C = 1 c) 2 AB + AB 1 = 828 \Rightarrow 257 + 571 = 828 So; A = 5; B = 7$