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Acceleration

position of a...

Question

position of a particle as a function of time is given as : x=t2 -4t+1. Find the speed of particle in 4 sec.

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Solution

$x = t^{2} - 4 t + 1 v e l o c i t y = \frac{d x}{d t} = 2 t - 4 a t t = 4 s, v e l o c i t y i s g i v e n b y : v = 2 \times 4 - 4 v = 4 m / s$

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